Skip to main content

ZOHO INTERVIEW QUESTION


QUESTION:

Find the next greater element for each element in given array.
input: array size=9;

        array[]={6, 3, 9, 10, 8, 2, 1, 15, 7};
output: {7, 5, 10, 15, 9, 3, 2, _, 8}


CODE:
#include<stdio.h>
#include<stdlib.h>
int main()
{
int n,b[100],c[100];
int i,j,p,temp;
scanf("%d",&n);
for(i=0;i<n;i++)
{
    scanf("%d",&b[i]);
    c[i]=b[i];
}
for(i=0;i<n;i++)
{
    p=i;
    for(j=i;j<n;j++)
    {
     if(c[p]>c[j])    
     p=j;
    }
    if(p!=i)
    {
        temp=c[i];
        c[i]=c[p];
        c[p]=temp;
    }
}
for(i=0;i<n;i++)
{
    for(j=0;j<n;j++)
    {
        if(b[i]==c[j] && j<(n-1))
        {
        printf("%d ",c[j+1]);
        break;
        }
        else if(b[i]==c[j] && j==(n-1))
        printf("_ ");
    }
}

}

Comments

Popular posts from this blog

zoho taxi question (3rd Round)

Taxi application Design a Call taxi booking application -There are n number of taxi’s. For simplicity, assume 4. But it should work for any number of taxi’s. -The are 6 points(A,B,C,D,E,F) -All the points are in a straight line, and each point is 15kms away from the adjacent points. -It takes 60 mins to travel from one point to another -Each taxi charges Rs.100 minimum for the first 5 kilometers and Rs.10 for the subsequent kilometers. -For simplicity, time can be entered as absolute time. Eg: 9hrs, 15hrs etc. -All taxi’s are initially stationed at A. -When a customer books a Taxi, a free taxi at that point is allocated -If no free taxi is available at that point, a free taxi at the nearest point is allocated. -If two taxi’s are free at the same point, one with lower earning is allocated -Note that the taxi only charges the customer from the pickup point to the drop point. Not the distance it travels from an adjacent point to pickup the customer. -If no taxi is free a...

Inser 0 after Consecutive (K times) Of 1 is Found

Example: Input: Number of bits: 12 Bits: 1 0 1 1 0 1 1 0 1 1 1 1 Consecutive K: 2 Output: 1 0 1 1 0 0 1 1 0 0 1 1 0 1 1 0 //JAVA CODE import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc= new Scanner(System. in ); int n = sc.nextInt(); int k=sc.nextInt(); int []a = new int [n]; int temp= 0 ; //Inputs for ( int i= 0 ;i<n;i++) a[i]=sc.nextInt(); //print for ( int i= 0 ;i<n;i++){ System. out .print(a[i]+ " " ); if (a[i]== 1 ){ temp++; if (temp==k) { System. out .print( "0 " ); temp= 0 ; } } else temp= 0 ; } } }

QUESTION You’re given an even number n. If n=4, you have to print the following pattern : 4444 4334 4334 4444 If n=6, then the pattern should be like this : 666666 655556 654456 654456 655556 666666

// JAVA CODE import java.util.*; import java.lang.*; import java.io.*; class zohoquestion{     public static void main(String args[]) {         Scanner sc= new Scanner(System.in);         int n=sc.nextInt();int limit=0;         int s=n;         int a[][]= new int[n][n];         int l=0;int r=n-1;         while(limit<n){             for(int i=l;i<=r;i++){                 for(int j=l;j<=r;j++)                     if(i==l || i==r || j==l || j==r)                     a[i][j]=n;             }             l++;r--;n--;limit++;         }         for(int i=0;i<s;i++){ ...